我在我的网站上进行了一项民意调查,该调查在每个答案旁边都显示了单选按钮。当用户选择一个选项并提交时,我通过ajax运行php脚本,以将值或选定的单选按钮插入表中。
我的Ajax正在运行,但当前每行插入一个0行,因此它没有从单选按钮中获取值。任何帮助,将不胜感激。
HTML:
<form id="poll_form" method="post" accept-charset="utf-8"> <input type="radio" name="poll_option" value="1" id="poll_option" /><label for='1'> Arts</label><br /> <input type="radio" name="poll_option" value="2" id="poll_option" /><label for='2'> Film</label><br /> <input type="radio" name="poll_option" value="3" id="poll_option" /><label for='3'> Games</label><br /> <input type="radio" name="poll_option" value="4" id="poll_option" /><label for='4'> Music</label><br /> <input type="radio" name="poll_option" value="5" id="poll_option" /><label for='5'> Sports</label><br /> <input type="radio" name="poll_option" value="6" id="poll_option" /><label for='6'> Television</label><br /> <input type="submit" value="Vote →" id="submit_vote" class="poll_btn"/> </form>
AJAX:
$("#submit_vote").click(function(e) { var option=$('input[type="radio"]:checked').val(); $optionID = "="+optionID; $.ajax({ type: "POST", url: "ajax_submit_vote.php", data: {"optionID" : $optionID} }); });
PHP :(简化版)
if($_SERVER['REQUEST_METHOD'] == "POST"){ //Get value from posted form $option = $_POST['poll_option']; //Insert into db $insert_vote = "INSERT into poll (userip,categoryid) VALUES ('$ip','$option')";
提前致谢!
$("#submit_vote").click(function(e){ $.ajax( { type: "POST", url: "ajax_submit_vote.php", data: $('#poll_form').serialize(), success: function( response ) {} }); });
然后,您应该在PHP脚本中可以访问POST变量“ poll_option”。