小编典典

POST 500(内部服务器错误)ajax,mvc

ajax

我有一个将数据发送到控制器的ajax请求,它收集我的下拉菜单的值

错误是

POST http://localhost:65070/form/create 500 (Internal Server Error)

错误的回应是

The required anti-forgery form field "__RequestVerificationToken" is not present.

更新 我的表格

@using (Html.BeginForm())
{
    @Html.AntiForgeryToken()
    @Html.ValidationSummary(true)

    <fieldset>
        <legend>Form</legend>

        <div class="editor-label">
            @Html.LabelFor(model => model.FormName)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.FormName)
            @Html.ValidationMessageFor(model => model.FormName)
        </div>


        <div class="editor-label">
            @Html.LabelFor(model => model.MasterID, "MasterModule")
        </div>
        <div class="editor-field">
            @Html.DropDownList("MasterID", String.Empty)
            @Html.ValidationMessageFor(model => model.MasterID)
        </div>
        <select id="State" name="state"></select><br />
        <p>
            <input type="submit" value="Create" />
        </p>

    </fieldset>
}

我的ajax请求

$('#State').change(function () {
  var a = $('#State').val();
    $.ajax({
                url: "/form/create",
                type: "POST",
                data: { 'SubID': a },
                success: function (result) {
                    //        console.log(result);
                }
            });
        });

我的控制器

public ActionResult Create(Form form, int SubID)
        {
            if (ModelState.IsValid)
            {
                form.SubId =SubID;
                form.CreatedDate = DateTime.Now;
                form.CreatedBy = 1;
                form.CreatedDate = DateTime.Now;
                form.IsActive = true;
                form.ModifyBy = 1;
                form.ModifyDate = DateTime.Now;

                db.Forms.Add(form);
                db.SaveChanges();
                return RedirectToAction("Index");
            }

            ViewBag.MasterID = new SelectList(db.Departments, "MasterId", "ModuleName", form.MasterID);
            return View(form);
        }

它给500内部错误..其笨拙的帮助


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2020-07-26

共1个答案

小编典典

您的post方法必须具有[ValidateAntiForgeryToken]属性。删除属性或在视图中添加令牌

@Html.AntiForgeryToken()

并将其传递回ajax函数

$('#State').change(function () {
  var a = $('#State').val();
  var token = $('[name=__RequestVerificationToken]').val();
  $.ajax({
    ....
    data: { __RequestVerificationToken: token, 'SubID': a },
    ....

请注意,该form参数在操作方法中不是必需的

[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult Create(int SubID)
{
  ....
2020-07-26