我有一个php / Ajax / Jquery脚本,该脚本将一个表单字段插入MySQL,并在您单击Submit时更新页面而不刷新。我希望脚本提交四个表单字段,而不只是一个。
我已经add_delete_record用3个其他字段更新了数据库表: 余额,account_number 和 month ,以及已经存在的内容字段。
add_delete_record
下面可能是代码的过大杀伤力,因为我只需要修改几行,但是我认为这可以回答所有问题。
这是php&html页面:
<div class="content_wrapper"> <ul id="responds"> <?php //include db configuration file include_once("config.php"); //MySQL query $Result = mysql_query("SELECT id,content FROM add_delete_record"); //get all records from add_delete_record table while($row = mysql_fetch_array($Result)) { echo '<li id="item_'.$row["id"].'">'; echo '<div class="del_wrapper"><a href="#" class="del_button" id="del-'.$row["id"].'">'; echo '<img src="images/icon_del.gif" border="0" />'; echo '</a></div>'; echo $row["content"].'</li>'; } //close db connection mysql_close($connecDB); ?> </ul> <div class="form_style"> <textarea name="content_txt" id="contentText" cols="45" rows="5"></textarea> <button id="FormSubmit">Add record</button> </div> </div>
这是它发布到的php:
<?php //include db configuration file include_once("config.php"); //check $_POST["content_txt"] is not empty if(isset($_POST["content_txt"]) && strlen($_POST["content_txt"])>0) { //sanitize post value, PHP filter FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH $contentToSave = filter_var($_POST["content_txt"],FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH); // Insert sanitize string in record if(mysql_query("INSERT INTO add_delete_record(content) VALUES('".$contentToSave."')")) { //Record is successfully inserted, respond to ajax request $my_id = mysql_insert_id(); //Get ID of last inserted record from MySQL echo '<li id="item_'.$my_id.'">'; echo '<div class="del_wrapper"><a href="#" class="del_button" id="del-'.$my_id.'">'; echo '<img src="images/icon_del.gif" border="0" />'; echo '</a></div>'; echo $contentToSave.'</li>'; mysql_close($connecDB); }else{ //output error //header('HTTP/1.1 500 '.mysql_error()); header('HTTP/1.1 500 Looks like mysql error, could not insert record!'); exit(); } } elseif(isset($_POST["recordToDelete"]) && strlen($_POST["recordToDelete"])>0 && is_numeric($_POST["recordToDelete"])) {//do we have a delete request? $_POST["recordToDelete"] //sanitize post value, PHP filter FILTER_SANITIZE_NUMBER_INT removes all characters except digits, plus and minus sign. $idToDelete = filter_var($_POST["recordToDelete"],FILTER_SANITIZE_NUMBER_INT); //try deleting record using the record ID we received from POST if(!mysql_query("DELETE FROM add_delete_record WHERE id=".$idToDelete)) { //If mysql delete record was unsuccessful, output error header('HTTP/1.1 500 Could not delete record!'); exit(); } mysql_close($connecDB); }else{ //Output error header('HTTP/1.1 500 Error occurred, Could not process request!'); exit(); } ?>
这是jQuery
$(document).ready(function() { //##### Add record when Add Record Button is clicked ######### $("#FormSubmit").click(function (e) { e.preventDefault(); if($("#contentText").val()==="") //simple validation { alert("Please enter some text!"); return false; } var myData = "content_txt="+ $("#contentText").val(); //post variables jQuery.ajax({ type: "POST", // HTTP method POST or GET url: "response.php", //Where to make Ajax calls dataType:"text", // Data type, HTML, json etc. data:myData, //post variables success:function(response){ $("#responds").append(response); $("#contentText").val(''); //empty text field after successful submission }, error:function (xhr, ajaxOptions, thrownError){ alert(thrownError); //throw any errors } }); }); //##### Delete record when delete Button is clicked ######### $("body").on("click", "#responds .del_button", function(e) { e.preventDefault(); var clickedID = this.id.split("-"); //Split string (Split works as PHP explode) var DbNumberID = clickedID[1]; //and get number from array var myData = 'recordToDelete='+ DbNumberID; //build a post data structure jQuery.ajax({ type: "POST", // HTTP method POST or GET url: "response.php", //Where to make Ajax calls dataType:"text", // Data type, HTML, json etc. data:myData, //post variables success:function(response){ //on success, hide element user wants to delete. $('#item_'+DbNumberID).fadeOut("slow"); }, error:function (xhr, ajaxOptions, thrownError){ //On error, we alert user alert(thrownError); } }); }); });
这不是我的脚本,所以我认为我也应该提供一个链接以感谢其作者:http : //www.sanwebe.com/2012/04/ajax-add-delete- sql-records-jquery-php
我不是php专家,但这应该可以帮助您:
首先更改主页上的表单区域:
<div class="form_style"> <textarea name="content_txt" id="contentText" cols="45" rows="5"></textarea><br/> <input type="text" id="balance" /><br/> <input type="text" id="acctNum" /><br/> <input type="text" id="monthly" /><br/> <button id="FormSubmit">Add record</button> </div>
那么您的myData看起来像这样:
var myData = { content_txt: $("#contentText").val(), balance: $("#balance").val(), acctNum: $("#acctNum").val(), monthly: $("#monthly").val() };
然后在ajax响应中:
$("#contentText").val(''); //empty text field after successful submission $("#balance").val(''); $("#acctNum").val(''); $("#monthly").val('');
最后是PHP:
//sanitize post value, PHP filter FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH $content = filter_var($_POST['content_txt'],FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH); $balance = filter_var($_POST['balance'],FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH); $account = filter_var($_POST['acctNum'],FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH); $monthly = filter_var($_POST['monthly'],FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH); $qry= "INSERT INTO add_delete_record(content,balance,account,monthly) VALUES('".$content."','".$balance."','".$account."','".$monthly."')"; // Insert sanitize string in record if(mysql_query("INSERT INTO add_delete_record(content,balance,account,monthly) VALUES('".$content."','".$balance."','".$account."','".$monthly."')")) { //Record is successfully inserted, respond to ajax request $my_id = mysql_insert_id(); //Get ID of last inserted record from MySQL echo '<li id="item_'.$my_id.'">'; echo '<div class="del_wrapper"><a href="#" class="del_button" id="del-'.$my_id.'">'; echo '<img src="images/icon_del.gif" border="0" />'; echo '</a></div>'; echo $content.'</li>'; mysql_close($connecDB); }else{ //output error //header('HTTP/1.1 500 '.mysql_error()); header('HTTP/1.1 500 Looks like mysql error, could not insert record!'); exit(); }