小编典典

Android-创建JSON数组和JSON对象

json

如何在Android中以这种格式创建JSON:由于我将传递的API将解析JsonArray,然后解析该对象。还是只传递一个json对象就可以了吗?因为我只需要在每个服务调用中插入1个事务即可。

{
    "student": [
        {
            "id": 1,
            "name": "John Doe",
            "year": "1st",
            "curriculum": "Arts",
            "birthday": 3/3/1995
        },
        {
            "id": 2,
            "name": "Michael West",
            "year": "2nd",
            "curriculum": "Economic",
            "birthday": 4/4/1994
        }
    ]
}

我所知道的只是JSONObject。像这个。

JSONObject obj = new JSONObject();
try {
    obj.put("id", "3");
    obj.put("name", "NAME OF STUDENT");
    obj.put("year", "3rd");
    obj.put("curriculum", "Arts");
    obj.put("birthday", "5/5/1993");
} catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

有任何想法吗。谢谢


阅读 358

收藏
2020-07-27

共1个答案

小编典典

使用以下代码:

JSONObject student1 = new JSONObject();
try {
    student1.put("id", "3");
    student1.put("name", "NAME OF STUDENT");
    student1.put("year", "3rd");
    student1.put("curriculum", "Arts");
    student1.put("birthday", "5/5/1993");

} catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

JSONObject student2 = new JSONObject();
try {
    student2.put("id", "2");
    student2.put("name", "NAME OF STUDENT2");
    student2.put("year", "4rd");
    student2.put("curriculum", "scicence");
    student2.put("birthday", "5/5/1993");

} catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}


JSONArray jsonArray = new JSONArray();

jsonArray.put(student1);
jsonArray.put(student2);

JSONObject studentsObj = new JSONObject();
    studentsObj.put("Students", jsonArray);



String jsonStr = studentsObj.toString();

    System.out.println("jsonString: "+jsonStr);
2020-07-27