iOS：通常从NSObject类序列化/反序列化复杂的JSON

小编典典

iOS：通常从NSObject类序列化/反序列化复杂的JSON

json

有人知道如何基于NSObject类序列化嵌套JSON吗？有序列化JSON简单的讨论在这里，但它不是一般的足够，以满足复杂的嵌套JSON。

想象这是JSON的结果：

{ "accounting" : [{ "firstName" : "John",  
                    "lastName"  : "Doe",
                    "age"       : 23 },

                  { "firstName" : "Mary",  
                    "lastName"  : "Smith",
                    "age"       : 32 }
                              ],                            
  "sales"      : [{ "firstName" : "Sally", 
                    "lastName"  : "Green",
                    "age"       : 27 },

                  { "firstName" : "Jim",   
                    "lastName"  : "Galley",
                    "age"       : 41 }
                  ]}

从这个班级：

@interface Person : NSObject{}
@property (nonatomic, strong) NSString *firstName;
@property (nonatomic, strong) NSString *lastName;
@property (nonatomic, strong) NSNumber *age;
@end

@interface Department : NSObject{}
@property (nonatomic, strong) NSMutableArray *accounting; //contain Person class
@property (nonatomic, strong) NSMutableArray *sales; //contain Person class
@end

如何基于类对它们进行序列化/反序列化？

编辑

目前，我可以基于任何类生成这样的有效负载：

NSMutableDictionary *Payload = [self serialize:objClass];

但是它不能满足嵌套的复杂JSON的要求。有人对此有更好的解决方案吗？该
C＃库可根据对象类进行序列化/反序列化。我想基于NSObject复制相同的东西

阅读 444

2020-07-27

共1个答案

小编典典

最后，我们可以使用JSONModel轻松解决此问题。这是迄今为止最好的方法。JSONModel是一个库，该库通常基于Class序列化/反序列化您的对象。你甚至可以使用基于像财产上的非NSObject的int，short和float。它还可以满足嵌套复杂的JSON。

1）反序列化示例 。通过参考上面的示例，在头文件中：

#import "JSONModel.h"

@interface Person : JSONModel 
@property (nonatomic, strong) NSString *firstName;
@property (nonatomic, strong) NSString *lastName;
@property (nonatomic, strong) NSNumber *age;
@end

@protocol Person;

@interface Department : JSONModel
@property (nonatomic, strong) NSMutableArray<Person> *accounting;
@property (nonatomic, strong) NSMutableArray<Person> *sales;
@end

在实现文件中：

#import "JSONModelLib.h"
#import "myJSONClass.h"

NSString *responseJSON = /*from example*/;
Department *department = [[Department alloc] initWithString:responseJSON error:&err];
if (!err)
{
    for (Person *person in department.accounting) {

        NSLog(@"%@", person.firstName);
        NSLog(@"%@", person.lastName);
        NSLog(@"%@", person.age);         
    }

    for (Person *person in department.sales) {

        NSLog(@"%@", person.firstName);
        NSLog(@"%@", person.lastName);
        NSLog(@"%@", person.age);         
    }
}

2）序列化示例 。在实现文件中：

#import "JSONModelLib.h"
#import "myJSONClass.h"

Department *department = [[Department alloc] init];

Person *personAcc1 = [[Person alloc] init];
personAcc1.firstName = @"Uee";
personAcc1.lastName = @"Bae";
personAcc1.age = [NSNumber numberWithInt:22];
[department.accounting addOject:personAcc1];

Person *personSales1 = [[Person alloc] init];
personSales1.firstName = @"Sara";
personSales1.lastName = @"Jung";
personSales1.age = [NSNumber numberWithInt:20];
[department.sales addOject:personSales1];

NSLog(@"%@", [department toJSONString]);

这是来自Serialize示例的NSLog结果：

{ "accounting" : [{ "firstName" : "Uee",  
                    "lastName"  : "Bae",
                    "age"       : 22 }
                 ],                            
  "sales"      : [{ "firstName" : "Sara", 
                    "lastName"  : "Jung",
                    "age"       : 20 }
                  ]}

2020-07-27