小编典典

如何反序列化其中包含无效字段名称的JSON对象

json

我有一个具有以下结构的JSON请求:

"formats":  {
        "flash_embed": "http://a3.vikiassets.com/assets/vikiplayer-922746a667cfd38137a7e45df6ba1b95.swf?auto_play=true&language_codes=en&media_id=74965&partner=16&source=api_v3",
        "m3u8": "http://wpc.354a.edgecastcdn.net/00354A/videos/encoded/74965/ios.m3u8",
        "res-150p": "http://wpc.354a.edgecastcdn.net/00354A/videos/encoded/74965_mp4cell_150.mp4",
        "res-240p": "http://wpc.354a.edgecastcdn.net/00354A/videos/encoded/74965_240p.mp4",
        "res-270p": "http://wpc.354a.edgecastcdn.net/00354A/videos/encoded/74965_270p.mp4",
        "res-360p": "http://wpc.354a.edgecastcdn.net/00354A/videos/encoded/74965_360p.mp4",
        "res-480p": "http://wpc.354a.edgecastcdn.net/00354A/videos/encoded/74965_480p.mp4",
        "res-720p": "http://wpc.354a.edgecastcdn.net/00354A/videos/encoded/74965_720p.mp4"
      }
    }

现在,res-150p在C#中说了无效的名称,如果我给它起了另一个名字,那么在进行反序列化时我没有得到任何值,res-150p内为空。

编辑: [可序列化] MoviesListRootObject是包含Response然后Response包含的根对象Formats

public class MoviesListRootObject
{
    public int count { get; set; }
    public Pagination pagination { get; set; }
    public List<Response> response { get; set; }
}

[Serializable]
public class Response
{
    public int id { get; set; }
    public int channel_id { get; set; }
    public string title { get; set; }
    public string title_language { get; set; }
    public string description { get; set; }
    public string description_language { get; set; }
    public string created_at { get; set; }
    public string uri { get; set; }
    public string web_uri { get; set; }
    public List<object> genres { get; set; }
    public string origin_country { get; set; }
    public string image { get; set; }
    public Subtitles subtitles { get; set; }
    public Formats formats { get; set; }
}

[Serializable]
public class Formats
{
    public string flash_embed { get; set; }
    public string m3u8 { get; set; }
    public string __invalid_name__res150p { get; set; }
    public string __invalid_name__res240p { get; set; }
    public string __invalid_name__res270p { get; set; }
    public string __invalid_name__res360p { get; set; }
    public string __invalid_name__res480p { get; set; }
    public string __invalid_name__res720p { get; set; }
    public string __invalid_name__flv480p { get; set; }
    public string __invalid_name__flv360p { get; set; }
    public string __invalid_name__flv270p { get; set; }
    public string __invalid_name__flvvp6360p { get; set; }
    public string __invalid_name__flvvp6270p { get; set; }
}

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2020-07-27

共1个答案

小编典典

您必须FormatsJsonProperty属性来修饰属性,以告诉它如果名称不完全匹配该怎么办:

partial class Formats
{
    [JsonProperty("res-150p")]
    public string __invalid_name__res150p {get; set;}
}

另请参见使用JsonConvert.DeserializeObject将Json反序列化为C#POCO类

2020-07-27