Json.net重命名属性

小编典典

Json.net重命名属性

json

我有一个表示JSON的字符串，我想使用JSON.NET重命名某些属性。我需要用于任何JSON的通用函数。就像是：

public static void Rename(JContainer container, Dictiontionary<string, string> mapping)
{
  foreach (JToken el in container.Children())
  {
    JProperty p = el as JProperty;
    if(el != null && mapping.ContainsKey(p.Name))
    {
      // **RENAME THIS NODE!!**
    }

    // recursively rename nodes
    JContainer pcont = el as JContainer;
    if(pcont != null)
    {
      Rename(pcont, mapping);
    }
  }
}

怎么做？？

阅读 347

2020-07-27

共1个答案

小编典典

我建议您使用重命名的属性来重构您的JSON。我认为您不必担心速度惩罚，因为通常这不是问题。这是您的操作方法。

public static JToken Rename(JToken json, Dictionary<string, string> map)
{
    return Rename(json, name => map.ContainsKey(name) ? map[name] : name);
}

public static JToken Rename(JToken json, Func<string, string> map)
{
    JProperty prop = json as JProperty;
    if (prop != null) 
    {
        return new JProperty(map(prop.Name), Rename(prop.Value, map));
    }

    JArray arr = json as JArray;
    if (arr != null)
    {
        var cont = arr.Select(el => Rename(el, map));
        return new JArray(cont);
    }

    JObject o = json as JObject;
    if (o != null)
    {
        var cont = o.Properties().Select(el => Rename(el, map));
        return new JObject(cont);
    }

    return json;
}

这是用法示例：

var s = @"{ ""A"": { ""B"": 1, ""Test"": ""123"", ""C"": { ""Test"": [ ""1"", ""2"", ""3"" ] } } }";
var json = JObject.Parse(s);

var renamed = Rename(json, name => name == "Test" ? "TestRenamed" : name);
renamed.ToString().Dump();  // LINQPad output

var dict = new Dictionary<string, string> { { "Test", "TestRenamed"} };
var renamedDict = Rename(json, dict);
renamedDict.ToString().Dump();  // LINQPad output

2020-07-27