如何在Play Json中使用Joda DateTime

小编典典

如何在Play Json中使用Joda DateTime

json

我正在开发Play应用程序，并且试图在我的case类中使用Joda DateTime对象。

package model

import org.joda.time.DateTime
import play.api.libs.json._

case class User(name: String, created: DateTime)

object User {
  implicit val yourJodaDateReads = Reads.jodaDateReads("yyyy-MM-dd'T'HH:mm:ss.SSSZ")
  implicit val yourJodaDateWrites = Writes.jodaDateWrites("yyyy-MM-dd'T'HH:mm:ss.SSSZ'")
  implicit val userFormat = Json.format[User]

  def main(args: Array[String]) {

  val value = Json.parse("{ \"name\" : \"hello\" , \"created\" : \"2015-07-16T20:32:04.046+02:00\" }")

  println(Json.toJson(new User("user", new DateTime())))
  println(Json.fromJson(value))
 }
}

基于此解决方案，出现此错误：

Error:(18, -1) Play 2 Compiler: 
 /activator-1.3.2/notifier-app/app/model/Test.scala:18: ambiguous implicit    values:
 both value yourJodaDateReads in object User of type => play.api.libs.json.Reads[org.joda.time.DateTime]
    and value userFormat in object User of type => play.api.libs.json.OFormat[model.User]

我正在使用Activator 1.3.2和Play 2.3.8。

你能给我建议吗？

提前致谢。

更新

我了解 play.api.libs.json.Reads中 的隐式值存在冲突 __

implicit val DefaultJodaDateReads = jodaDateReads("yyyy-MM-dd")

我该如何解决这个问题？

阅读 265

2020-07-27

共1个答案

小编典典

期待更好的选择，这是我的解决方法：

val dateFormat = "yyyy-MM-dd'T'HH:mm:ss.SSSZ"

val jodaDateReads = Reads[DateTime](js =>
  js.validate[String].map[DateTime](dtString =>
    DateTime.parse(dtString, DateTimeFormat.forPattern(dateFormat))
  )
)

val jodaDateWrites: Writes[DateTime] = new Writes[DateTime] {
  def writes(d: DateTime): JsValue = JsString(d.toString())
}

val userReads: Reads[User] = (
  (JsPath \ "name").read[String] and
    (JsPath \ "created").read[DateTime](jodaDateReads)
  )(User.apply _)

val userWrites: Writes[User] = (
  (JsPath \ "name").write[String] and
   (JsPath \ "created").write[DateTime](jodaDateWrites)
  )(unlift(User.unapply))

implicit val userFormat: Format[User] = Format(userReads, userWrites)

2020-07-27