小编典典

使用Json.Net解析Google Maps地理编码json响应到对象

json

我有一个充满地址的数据库,我需要获取经纬度,并且需要很长一段时间,因此我想遍历它们并使用Google
Geocode更新我的数据库。我对如何解析JSOn结果以获取所需信息感到困惑:

var address = "http://maps.google.com/maps/api/geocode/json?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA&sensor=false";
var result = new System.Net.WebClient().DownloadString(address);
GoogleGeoCodeResponse test = JsonConvert.DeserializeObject<GoogleGeoCodeResponse>(result);

我以为我可以简单地建立一个快速的类,并使用JSON.Net对结果进行反序列化,这是可行的,但是我想在类结构中使用它:

public  class GoogleGeoCodeResponse {

    public string status { get; set; }
    public geometry geometry { get; set; }

}

public class geometry {
    public string location_type { get; set; }
    public location location { get; set; }
}

public class location {
    public string lat {get;set;}
    public string lng {get;set;}
}

以下是Google返回的示例:

{
  "status": "OK",
  "results": [ {
    "types": [ "street_address" ],
    "formatted_address": "1600 Amphitheatre Pkwy, Mountain View, CA 94043, USA",
    "address_components": [ {
      "long_name": "1600",
      "short_name": "1600",
      "types": [ "street_number" ]
    }, {
      "long_name": "Amphitheatre Pkwy",
      "short_name": "Amphitheatre Pkwy",
      "types": [ "route" ]
    }, {
      "long_name": "Mountain View",
      "short_name": "Mountain View",
      "types": [ "locality", "political" ]
    }, {
      "long_name": "California",
      "short_name": "CA",
      "types": [ "administrative_area_level_1", "political" ]
    }, {
      "long_name": "United States",
      "short_name": "US",
      "types": [ "country", "political" ]
    }, {
      "long_name": "94043",
      "short_name": "94043",
      "types": [ "postal_code" ]
    } ],
    "geometry": {
      "location": {
        "lat": 37.4219720,
        "lng": -122.0841430
      },
      "location_type": "ROOFTOP",
      "viewport": {
        "southwest": {
          "lat": 37.4188244,
          "lng": -122.0872906
        },
        "northeast": {
          "lat": 37.4251196,
          "lng": -122.0809954
        }
      }
    }
  } ]
}

我在这里想念简单,有人吗?


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2020-07-27

共1个答案

小编典典

我尝试了一下,做了一个简单的测试,并成功了(增加了结果和其他):

public class GoogleGeoCodeResponse
{

    public string status { get; set; }
    public results[] results { get; set; }

}

public class results
{
    public string formatted_address { get; set; }
    public geometry geometry { get; set; }
    public string[] types { get; set; }
    public address_component[] address_components { get; set; }
}

public class geometry
{
    public string location_type { get; set; }
    public location location { get; set; }
}

public class location
{
    public string lat { get; set; }
    public string lng { get; set; }
}

public class address_component
{
    public string long_name { get; set; }
    public string short_name { get; set; }
    public string[] types { get; set; }
}
2020-07-27