小编典典

使用AFNetworking发送嵌套的JSON

json

要将注册数据发送到服务器,我使用的JSON格式如下:

{"regData": {
 "City":"Some City",
 "Country":"Some Country",
 "Email_Id":"abc@gmail.com",
 "MobileNumber":"+00xxxxxxxxxx",
 "UserName":"Name Of user"
 }
}

这是发送方式。

 NSURL * url = [[NSURL alloc] initWithString:registerUrlString];
            AFHTTPClient * httpClient = [[AFHTTPClient alloc] initWithBaseURL:url];
            httpClient.parameterEncoding = AFJSONParameterEncoding;
            [[AFNetworkActivityIndicatorManager sharedManager] setEnabled:YES];
            NSDictionary * params = @{@"regData": @{
                                              @"City": self.cityField.text,
                                              @"Country": self.countryField.text,
                                              @"Email_Id": self.emailField.text,
                                              @"MobileNumber": self.numberField.text,
                                              @"UserName": self.userName.text,
                                              }
                                      };

            NSMutableURLRequest * request = [httpClient requestWithMethod:@"POST" path:registerUrlString parameters:params];
            AFHTTPRequestOperation * operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:request success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON) {
                NSLog(@"Success: %@", JSON);

            } failure:^(NSURLRequest *request, NSHTTPURLResponse *response, NSError *error, id JSON) {
            NSLog(@"Error: %@", [error debugDescription]);
            }];

            [operation start];

但不幸的是,我收到此错误:

Error Domain=NSCocoaErrorDomain Code=3840 "The operation couldn’t be completed. (Cocoa error 3840.)" (JSON text did not start with array or object and option to allow fragments not set.) UserInfo=0x94b3c30 {NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.}


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2020-07-27

共1个答案

小编典典

您的要求很好。Error Domain=NSCocoaErrorDomain Code=3840由于服务器使用无效的JSON对象进行响应,因此将返回错误。NSLog
operation.responseString看看发回了什么。

2020-07-27