C＃是否具有用于解析多级级联JSON的库？

小编典典

C＃是否具有用于解析多级级联JSON的库？

json

是否有一个库（首选C＃）来解决我称为多级层叠JSON的问题？

这是我的意思的示例： （Pseudocode / C＃）

var json1 = @"{
    ""firstName"": ""John"",
    ""lastName"": ""Smith""
    }";

var json2 = @"{
    ""firstName"": ""Albert""
    }";

var json3 = @"{
    ""phone"": ""12345""
    }";

var cascadingJSON = JSON.Cascade(json1, json2, json3);

结果（行为与CSS相同）

{
    "firstName"": "Albert", /*Overridden*/
    "lastName"": "Smith", /*Inherited*/
    "phone"": "12345"   }"; /*Added*/
}

编辑1-更复杂的示例

const string json1 =
                @"{
                     ""firstName"": ""John"",
                     ""lastName"": ""Smith"",
                     ""age"": 25,
                     ""address"": 
                     {
                         ""streetAddress"": ""21 2nd Street"",
                         ""city"": ""New York"",
                         ""state"": ""NY"",
                         ""postalCode"": ""10021""
                     },
                     ""phoneNumber"": 
                     [
                         {
                           ""type"": ""home"",
                           ""number"": ""212 555-1234""
                         },
                         {
                           ""type"": ""fax"",
                           ""number"": ""646 555-4567""
                         }
                     ]
                 }";

            const string json2 =
                @"{
                     ""firstName"": ""John2"",
                     ""lastName"": ""robert"",
                     ""age"": 25,
                     ""address"": 
                     {
                         ""state"": ""FL"",
                     },
                     ""phoneNumber"": 
                     [
                         {
                           ""type"": ""fax"",
                           ""number"": ""222 222-2222""
                         },
                         {
                           ""type"": ""iphone"",
                           ""number"": ""111 111-1111""
                         }
                     ]
                 }";

            const string json3 =
                @"{
                     ""firstName"": ""John3"",
                     ""father"": ""guy""
                 }";

            const string expectedResult =
                @"{
                     ""firstName"": ""John3"",
                     ""lastName"": ""robert"",
                     ""age"": 25,
                     ""father"": ""guy"",
                     ""address"": 
                     {
                         ""streetAddress"": ""21 2nd Street"",
                         ""city"": ""New York"",
                         ""state"": ""FL"",
                         ""postalCode"": ""10021""
                     },
                     ""phoneNumber"": 
                     [
                         {
                           ""type"": ""home"",
                           ""number"": ""212 555-1234""
                         },
                         {
                           ""type"": ""fax"",
                           ""number"": ""222 222-2222""
                         },
                         {
                           ""type"": ""iphone"",
                           ""number"": ""111 111-1111""
                         }
                     ]
                 }";

编辑2

在对需求进行了更多思考之后，我看到了更复杂的示例永远无法按原样工作。例如，级联功能将无法知道某个电话号码是否已被修改，或者它是否是新的。为了使其工作，每个子实体都应具有唯一的标识符。

阅读 317

2020-07-27

共1个答案

小编典典

使用出色的JSON.NET库，这非常容易。此方法将对象与具有字符串，数字或对象的属性组合在一起。

public static string Cascade(params string[] jsonArray)
{
    JObject result = new JObject();
    foreach (string json in jsonArray)
    {
        JObject parsed = JObject.Parse(json);
        foreach (var property in parsed)
            result[property.Key] = property.Value;
    }
    return result.ToString();
}

结果，给出您的示例：

{
  "firstName": "Albert",
  "lastName": "Smith",
  "phone": "12345"
}

根据您更新的问题进行编辑：

通过将该解决方案调整为递归工作，可以合并子对象。下面的示例将符合您的预期结果（数组除外）。您将能够JArray以类似于合并对象（JObject）的方式轻松扩展此解决方案以合并数组（）。

public static string Cascade(params string[] jsonArray)
{
    JObject result = new JObject();
    foreach (string json in jsonArray)
    {
        JObject parsed = JObject.Parse(json);
        Merge(result, parsed);
    }
    return result.ToString();
}

private static void Merge(JObject receiver, JObject donor)
{
    foreach (var property in donor)
    {
        JObject receiverValue = receiver[property.Key] as JObject;
        JObject donorValue = property.Value as JObject;
        if (receiverValue != null && donorValue != null)
            Merge(receiverValue, donorValue);
        else
            receiver[property.Key] = property.Value;
    }
}

2020-07-27