小编典典

原始类型的Jackson序列化器

json

我正在编写一个自定义序列化程序,以将双精度值转换为JSON对象中的字符串。到目前为止,我的代码:

public String toJson(Object obj) throws IOException {
    ObjectMapper mapper = new ObjectMapper();
    SimpleModule module = new SimpleModule("DoubleSerializer", new Version(1, 0, 0, ""));

    module.addSerializer(Double.class, new DoubleSerializer());
    mapper.registerModule(module);
    return mapper.writeValueAsString(obj);
}

public class DoubleSerializer extends JsonSerializer<Double> {
    @Override
    public void serialize(Double value, JsonGenerator jgen,
            SerializerProvider provider) throws IOException,
            JsonProcessingException {
        String realString = new BigDecimal(value).toPlainString();
        jgen.writeString(realString);
    }
}

这对于Double(类成员)非常有效,但不适用于double(原始类型)成员。例如,

    public void test() throws IOException {
        JsonMaker pr = new JsonMaker();
        TestClass cl = new TestClass();

        System.out.println(pr.toJson(cl));

    }

    class TestClass {
        public Double x;
        public double y;
        public TestClass() {
            x = y = 1111142143543543534645145325d;
        }
    }

返回:{“ x”:“ 1111142143543543565865975808”,“ y”:1.1111421435435436E27}

有没有办法让这两种情况都遵循相同的行为?


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2020-07-27

共1个答案

小编典典

您可以JsonSerializer为原始类型注册double

module.addSerializer(double.class, new DoubleSerializer());
2020-07-27