小编典典

反应:“ this”在组件函数中未定义

javascript

class PlayerControls extends React.Component {
  constructor(props) {
    super(props)

    this.state = {
      loopActive: false,
      shuffleActive: false,
    }
  }

  render() {
    var shuffleClassName = this.state.toggleActive ? "player-control-icon active" : "player-control-icon"

    return (
      <div className="player-controls">
        <FontAwesome
          className="player-control-icon"
          name='refresh'
          onClick={this.onToggleLoop}
          spin={this.state.loopActive}
        />
        <FontAwesome
          className={shuffleClassName}
          name='random'
          onClick={this.onToggleShuffle}
        />
      </div>
    );
  }

  onToggleLoop(event) {
    // "this is undefined??" <--- here
    this.setState({loopActive: !this.state.loopActive})
    this.props.onToggleLoop()
  }

我想loopActive在切换时更新状态,但this在处理程序中未定义对象。根据教程文档,我this应该引用该组件。我想念什么吗?


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2020-04-25

共1个答案

小编典典

ES6 React.Component不会自动将方法绑定到自身。您需要将它们自己绑定到构造函数中。像这样:

constructor (props){
  super(props);

  this.state = {
      loopActive: false,
      shuffleActive: false,
    };

  this.onToggleLoop = this.onToggleLoop.bind(this);

}
2020-04-25