我试图在排列列表中找到给定字符串的排名，并希望有人可以找到该错误。

function permute() {
    var W = $('input').val(),
        C = [];
    for (var i = 0; i < 26; i++) C[i] = 0;
    var rank = 1;
    for (var i = 0; i < W.length; i++) {
        C[W.charCodeAt(i) - 'a'.charCodeAt(0)]++;
    }
    var repeated= 1;
    for (var i = 0; i < C.length; i++) {
        if(C[i] > 0) {
            repeated *=  fact(C[i]);
        }
    }

    if (W !== '') {
        for (var i = 0; i < W.length; i++) {
            //How many characters which are not used, that come before current character
            var count = 0;
            for (var j = 0; j < 26; j++) {
                if (j == (W.charCodeAt(i) - 'a'.charCodeAt(0))) break;
                if (C[j] > 0) count++;
            }
            C[W.charCodeAt(i) - 'a'.charCodeAt(0)] = 0;
            rank += ( count * fact(W.length - i - 1) );
        }
        rank = rank/ repeated;
    }
    var pp = 'Rank of  :: ' + W + ' -- ' + rank;
    $('div').append('<p>' + pp + '</p>');
}

function fact(n) {
    if (n == 0 || n == 1) return 1;
    else return fact(n - 1) * n;
}

$('button').click(permute);

检查小提琴

一个用例可能是

bookkeeper应该被 评为10743 。