小编典典

如何打破递归函数的循环?

algorithm

我正在使用可以包含子类别对象数组的类别对象数组。棘手的部分是,此嵌套数据的深度是未知的(并且可以更改)。(请参阅底部的示例。)我要做的是将“线索”返回到类别对象,但是我遇到了各种各样的困难。

理想情况下,findCategory('b4')将返回:(['c1', 'd2', 'd3', 'b4']请参阅示例)。

我认为我的问题是我无法正确打破由递归引起的嵌套循环。有时,我会在路径中获得更多类别,或者当我认为自己已经突破时,一些更深层的嵌套类别最终会出现在路径中。

一个结果可能看起来像这样。显然,这并没有杀死b4处的循环,而且我不确定为什么会两次发现结果。

b4
FOUND
["c1", "d2", "d3", "b4"]
e2
FOUND
["c1", "d2", "d3", "b4", "e2"]

奖励,如果您还可以给我看一个underscore.js版本。

JSFiddle链接在这里…

// Start function
function findCategory(categoryName) {
    var trail = [];
    var found = false;

    function recurse(categoryAry) {

        for (var i=0; i < categoryAry.length; i++) {
            console.log(categoryAry[i].category);
            trail.push(categoryAry[i].category);

            // Found the category!
            if ((categoryAry[i].category === categoryName) || found) {
                console.log('FOUND');
                found = true;
                console.log(trail);
                break;

            // Did not match...
            } else {

                // Are there children / sub-categories? YES
                if (categoryAry[i].children.length > 0) {

                    console.log('recurse');
                    recurse(categoryAry[i].children);

                // NO
                } else {
                    trail.pop();
                    if (i === categoryAry.length - 1) {
                        trail.pop();
                    }
                }
            }

        } 
    }

    return recurse(catalog);
}

console.clear();
console.log(findCategory('b4'));

例如,数组类别对象和类别对象的嵌套数组。假设嵌套深度未知。

var catalog = [
{
    category:"a1",
    children:[
        {
            category:"a2",
            children:[]
        },
        {
            category:"b2",
            children:[
                {
                    category:"a3",
                    children:[]
                },
                {
                    category:"b3",
                    children:[]
                }
            ]
        },
        {
            category:"c2",
            children:[]
        }
    ]
},
{
    category:"b1",
    children:[]
},
{
    category:"c1",
    children:[
        {
            category:"d2",
            children:[
                {
                    category:"c3",
                    children:[]
                },
                {
                    category:"d3",
                    children:[
                        {
                            category:"a4",
                            children:[]
                        },
                        {
                            category:"b4",
                            children:[]
                        },
                        {
                            category:"c4",
                            children:[]
                        },
                        {
                            category:"d4",
                            children:[]
                        }
                    ]
                }
            ]
        },
        {
            category:"e2",
            children:[
                {
                    category:"e3",
                    children:[]
                }
            ]
        }
    ]
}
];

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2020-07-28

共1个答案

小编典典

尝试

function findCategory(categoryName) {
    var trail = [];
    var found = false;

    function recurse(categoryAry) {

        for (var i = 0; i < categoryAry.length; i++) {
            trail.push(categoryAry[i].category);

            // Found the category!
            if ((categoryAry[i].category === categoryName)) {
                found = true;
                break;

                // Did not match...
            } else {
                // Are there children / sub-categories? YES
                if (categoryAry[i].children.length > 0) {
                    recurse(categoryAry[i].children);
                    if(found){
                        break;
                    }
                }
            }
            trail.pop();
        }
    }

    recurse(catalog);

    return trail
}

演示:小提琴

2020-07-28