我希望能够从Java操作方法中的JSON字符串访问属性。只需说一下即可使用该字符串myJsonString = object.getJson()。下面是该字符串的示例:
myJsonString = object.getJson()
{ 'title': 'ComputingandInformationsystems', 'id': 1, 'children': 'true', 'groups': [{ 'title': 'LeveloneCIS', 'id': 2, 'children': 'true', 'groups': [{ 'title': 'IntroToComputingandInternet', 'id': 3, 'children': 'false', 'groups': [] }] }] }
在此字符串中,每个JSON对象都包含其他JSON对象的数组。目的是提取ID列表,其中任何给定对象都具有包含其他JSON对象的group属性。我将Google的Gson视为潜在的JSON插件。谁能提供某种形式的指导,说明如何从此JSON字符串生成Java?
我将Google的Gson视为潜在的JSON插件。谁能提供某种形式的指导,说明如何从此JSON字符串生成Java?
Google Gson支持泛型和嵌套bean。[]JSON中的in表示一个数组,应映射到Java集合,例如List或仅映射到普通Java数组。{}JSON中的in代表一个对象,应映射到Java Map或某些JavaBean类。
你有一个带有多个属性的JSON对象,这些属性的groups属性表示同一类型的嵌套对象的数组。可以通过以下方式使用Gson进行解析:
package com.codingdict; import java.util.List; import com.google.gson.Gson; public class Test { public static void main(String... args) throws Exception { String json = "{" + "'title': 'Computing and Information systems'," + "'id' : 1," + "'children' : 'true'," + "'groups' : [{" + "'title' : 'Level one CIS'," + "'id' : 2," + "'children' : 'true'," + "'groups' : [{" + "'title' : 'Intro To Computing and Internet'," + "'id' : 3," + "'children': 'false'," + "'groups':[]" + "}]" + "}]" + "}"; // Now do the magic. Data data = new Gson().fromJson(json, Data.class); // Show it. System.out.println(data); } } class Data { private String title; private Long id; private Boolean children; private List<Data> groups; public String getTitle() { return title; } public Long getId() { return id; } public Boolean getChildren() { return children; } public List<Data> getGroups() { return groups; } public void setTitle(String title) { this.title = title; } public void setId(Long id) { this.id = id; } public void setChildren(Boolean children) { this.children = children; } public void setGroups(List<Data> groups) { this.groups = groups; } public String toString() { return String.format("title:%s,id:%d,children:%s,groups:%s", title, id, children, groups); } }