Python django.contrib.admin.helpers 模块，AdminErrorList() 实例源码

def add_type_view(self, request, form_url=''):
        """
        Display a choice form to select which page type to add.
        """
        if not self.has_add_permission(request):
            raise PermissionDenied

        extra_qs = ''
        if request.META['QUERY_STRING']:
            extra_qs = '&' + request.META['QUERY_STRING']

        choices = self.get_child_type_choices(request, 'add')
        if len(choices) == 1:
            return HttpResponseRedirect('?ct_id={0}{1}'.format(choices[0][0], extra_qs))

        # Create form
        form = self.add_type_form(
            data=request.POST if request.method == 'POST' else None,
            initial={'ct_id': choices[0][0]}
        )
        form.fields['ct_id'].choices = choices

        if form.is_valid():
            return HttpResponseRedirect('?ct_id={0}{1}'.format(form.cleaned_data['ct_id'], extra_qs))

        # Wrap in all admin layout
        fieldsets = ((None, {'fields': ('ct_id',)}),)
        adminForm = AdminForm(form, fieldsets, {}, model_admin=self)
        media = self.media + adminForm.media
        opts = self.model._meta

        context = {
            'title': _('Add %s') % force_text(opts.verbose_name),
            'adminform': adminForm,
            'is_popup': ("_popup" in request.POST or
                         "_popup" in request.GET),
            'media': mark_safe(media),
            'errors': AdminErrorList(form, ()),
            'app_label': opts.app_label,
        }
        return self.render_add_type_form(request, context, form_url)