我们从Python开源项目中,提取了以下5个代码示例,用于说明如何使用django.contrib.admin.utils.NotRelationField()。
def validate_list_filter(self, cls, model): """ Validate that list_filter is a sequence of one of three options: 1: 'field' - a basic field filter, possibly w/ relationships (eg, 'field__rel') 2: ('field', SomeFieldListFilter) - a field-based list filter class 3: SomeListFilter - a non-field list filter class """ from django.contrib.admin import ListFilter, FieldListFilter if hasattr(cls, 'list_filter'): check_isseq(cls, 'list_filter', cls.list_filter) for idx, item in enumerate(cls.list_filter): if callable(item) and not isinstance(item, models.Field): # If item is option 3, it should be a ListFilter... if not issubclass(item, ListFilter): raise ImproperlyConfigured("'%s.list_filter[%d]' is '%s'" " which is not a descendant of ListFilter." % (cls.__name__, idx, item.__name__)) # ... but not a FieldListFilter. if issubclass(item, FieldListFilter): raise ImproperlyConfigured("'%s.list_filter[%d]' is '%s'" " which is of type FieldListFilter but is not" " associated with a field name." % (cls.__name__, idx, item.__name__)) else: if isinstance(item, (tuple, list)): # item is option #2 field, list_filter_class = item if not issubclass(list_filter_class, FieldListFilter): raise ImproperlyConfigured("'%s.list_filter[%d][1]'" " is '%s' which is not of type FieldListFilter." % (cls.__name__, idx, list_filter_class.__name__)) else: # item is option #1 field = item # Validate the field string try: get_fields_from_path(model, field) except (NotRelationField, FieldDoesNotExist): raise ImproperlyConfigured("'%s.list_filter[%d]' refers to '%s'" " which does not refer to a Field." % (cls.__name__, idx, field))