我们从Python开源项目中，提取了以下50个代码示例，用于说明如何使用symbol.test()。
def get_op(cls, op): ops = { symbol.test: cls.test, symbol.and_test: cls.and_test, symbol.atom: cls.atom, symbol.comparison: cls.comparison, 'not in': lambda x, y: x not in y, 'in': lambda x, y: x in y, '==': operator.eq, '!=': operator.ne, '<': operator.lt, '>': operator.gt, '<=': operator.le, '>=': operator.ge, } if hasattr(symbol, 'or_test'): ops[symbol.or_test] = cls.test return ops[op]
def print_stmt(self, nodelist): # print ([ test (',' test)* [','] ] | '>>' test [ (',' test)+ [','] ]) items = [] if len(nodelist) == 1: start = 1 dest = None elif nodelist[1][0] == token.RIGHTSHIFT: assert len(nodelist) == 3 \ or nodelist[3][0] == token.COMMA dest = self.com_node(nodelist[2]) start = 4 else: dest = None start = 1 for i in range(start, len(nodelist), 2): items.append(self.com_node(nodelist[i])) if nodelist[-1][0] == token.COMMA: return Print(items, dest, lineno=nodelist[0][2]) return Printnl(items, dest, lineno=nodelist[0][2])
def com_argument(self, nodelist, kw, star_node): if len(nodelist) == 3 and nodelist[2][0] == symbol.comp_for: test = self.com_node(nodelist[1]) return 0, self.com_generator_expression(test, nodelist[2]) if len(nodelist) == 2: if kw: raise SyntaxError, "non-keyword arg after keyword arg" if star_node: raise SyntaxError, "only named arguments may follow *expression" return 0, self.com_node(nodelist[1]) result = self.com_node(nodelist[3]) n = nodelist[1] while len(n) == 2 and n[0] != token.NAME: n = n[1] if n[0] != token.NAME: raise SyntaxError, "keyword can't be an expression (%s)"%n[0] node = Keyword(n[1], result, lineno=n[2]) return 1, node
def test(cls, nodelist): # MUST NOT short-circuit evaluation, or invalid syntax can be skipped! return functools.reduce(operator.or_, [cls.interpret(nodelist[i]) for i in range(1,len(nodelist),2)])
def get_op(cls, op): ops = { symbol.test: cls.test, symbol.and_test: cls.and_test, symbol.atom: cls.atom, symbol.comparison: cls.comparison, 'not in': lambda x, y: x not in y, 'in': lambda x, y: x in y, '==': operator.eq, '!=': operator.ne, } if hasattr(symbol, 'or_test'): ops[symbol.or_test] = cls.test return ops[op]
def test(cls, nodelist): # MUST NOT short-circuit evaluation, or invalid syntax can be skipped! items = [ cls.interpret(nodelist[i]) for i in range(1, len(nodelist), 2) ] return functools.reduce(operator.or_, items)
