Java.util.Scanner.nextInt()

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描述

所述java.util.Scanner.nextInt()方法扫描输入作为表单nextInt(此方法的一个int.An调用的下一个标记)的行为以完全相同的方式调用nextInt(),其中基数是此扫描仪的默认基数。

声明

以下是java.util.Scanner.nextInt()方法的声明

public int nextInt()

参数

NA

返回值

此方法返回从输入中扫描的int

异常

InputMismatchException - 如果下一个标记与Integer正则表达式不匹配,或者超出范围

NoSuchElementException - 如果输入已用尽

IllegalStateException - 如果此扫描程序已关闭

实例

以下示例显示了java.util.Scanner.nextInt()方法的用法。

package com.tutorialspoint;

import java.util.*;

public class ScannerDemo {
   public static void main(String[] args) {

      String s = "Hello World! 3 + 3.0 = 6.0 true ";

      // create a new scanner with the specified String Object
      Scanner scanner = new Scanner(s);

      // find the next int token and print it
      // loop for the whole scanner
      while (scanner.hasNext()) {

         // if the next is a int, print found and the int
         if (scanner.hasNextInt()) {
            System.out.println("Found :" + scanner.nextInt());
         }
         // if no int is found, print "Not Found:" and the token
         System.out.println("Not Found :" + scanner.next());
      }

      // close the scanner
      scanner.close();
   }
}

让我们编译并运行上面的程序,这将产生以下结果

Not Found :Hello
Not Found :World!
Found :3
Not Found :+
Not Found :3.0
Not Found :=
Not Found :6.0
Not Found :true