jQuery Ajax Post方法


发送异步http POST请求以从服务器加载数据。其一般形式是:

jQuery.post( url [, data ] [, success ] [, dataType ] )
  • url:是唯一的必需参数。此字符串包含要将请求发送到的地址。如果未指定其他参数,则将忽略返回的数据
  • data:与请求一起发送到服务器的普通对象或字符串。
  • success:如果请求成功则执行的回调函数。它将返回的数据作为参数。它还传递了响应的文本状态。
  • dataType:服务器所需的数据类型。默认为Intelligent Guess(xml,json,script,text,html)。如果提供了此参数,则还必须提供成功回调。

例子

$.post('http://example.com/form.php', {category:'client', type:'premium'});

从服务器请求form.php ,发送附加数据并忽略返回的结果

$.post('http://example.com/form.php', {category:'client', type:'premium'}, function(response){
      alert("success");
      $("#mypar").html(response.amount);
 });

从服务器请求form.php ,发送附加数据并处理返回的响应(json格式)。此示例可以使用以下格式编写:

$.post('http://example.com/form.php', {category:'client', type:'premium'}).done(function(response){
      alert("success");
      $("#mypar").html(response.amount);
 });

以下示例使用Ajax发布表单并将结果放入div

<!doctype html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <title>jQuery.post demo</title>
  <script src="https://code.jquery.com/jquery-1.10.2.js"></script>
</head>
<body>

<form action="/" id="searchForm">
  <input type="text" name="s" placeholder="Search...">
  <input type="submit" value="Search">
</form>
<!-- the result of the search will be rendered inside this div -->
<div id="result"></div>

<script>
// Attach a submit handler to the form
$( "#searchForm" ).submit(function( event ) {

  // Stop form from submitting normally
  event.preventDefault();

  // Get some values from elements on the page:
  var $form = $( this ),
    term = $form.find( "input[name='s']" ).val(),
    url = $form.attr( "action" );

  // Send the data using post
  var posting = $.post( url, { s: term } );

  // Put the results in a div
  posting.done(function( data ) {
    var content = $( data ).find( "#content" );
    $( "#result" ).empty().append( content );
  });
});
</script>

</body>
</html>

The following example use the github api to fetch the list of repositories of a user using jQuery.ajax() and put results in a div

<!doctype html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <title>jQuery Get demo</title>
  <script src="https://code.jquery.com/jquery-1.10.2.js"></script>
</head>
<body>

<form id="userForm">
  <input type="text" name="username" placeholder="Enter gitHub User name">
  <input type="submit" value="Search">
</form>
<!-- the result of the search will be rendered inside this div -->
<div id="result"></div>

<script>
// Attach a submit handler to the form
$( "#userForm" ).submit(function( event ) {

  // Stop form from submitting normally
  event.preventDefault();

  // Get some values from elements on the page:
  var $form = $( this ),
    username = $form.find( "input[name='username']" ).val(),
    url = "https://api.github.com/users/"+username+"/repos";

  // Send the data using post
  var posting = $.post( url, { s: term } );

  //Ajax Function to send a get request
  $.ajax({
    type: "GET",
    url: url,
    dataType:"jsonp"
    success: function(response){
        //if request if made successfully then the response represent the data

        $( "#result" ).empty().append( response );
    }
  });

});
</script>

</body>
</html>

jQuery.ajax()

$.post( url [, data ] [, success ] [, dataType ] ) is a shorthand Ajax function, equivalent to:

$.ajax({
  type: "POST",
  url: url,
  data: data,
  success: success,
  dataType: dataType
});

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