java算法-打印从 1 到最大的 n 位数

/**
 * @author bingo
 * @since 2018/11/20
 */

public class Solution {

    /**
     * 打印从1到最大的n位数
     * @param n n位
     */
    public void print1ToMaxOfNDigits(int n) {
        if (n < 1) {
            return;
        }

        char[] chars = new char[n];
        for (int i = 0; i < n; ++i) {
            chars[i] = '0';
        }

        while (!increment(chars)) {
            printNumber(chars);
        }
    }

    /**
     * 打印数字（去除前面的0）
     * @param chars 数字数组
     */
    private void printNumber(char[] chars) {
        int index = 0;
        int n = chars.length;
        for (char ch : chars) {
            if (ch != '0') {
                break;
            }
            ++index;
        }
        StringBuilder sb = new StringBuilder();
        for (int i = index; i < n; ++i) {
            sb.append(chars[i]);
        }
        System.out.println(sb.toString());
    }

    /**
     * 数字加1
     * @param chars 数字数组
     * @return 是否溢出
     */
    private boolean increment(char[] chars) {
        boolean flag = false;
        int n = chars.length;
        int carry = 1;
        for (int i = n - 1; i >= 0; --i) {

            int num = chars[i] - '0' + carry;
            if (num > 9) {
                if (i == 0) {
                    flag = true;
                    break;
                }
                chars[i] = '0';
            } else {
                ++chars[i];
                break;
            }
        }
        return flag;
    }
}