C示例程序搜索字符串 C示例用于反转String的程序 C实例 交互字符串 C示例程序搜索字符串 #include <stdio.h> #include <string.h> int main() { char s1[] = "Beauty is in the eye of the beholder"; char s2[] = "the"; int n = 0; int m = 0; int times = 0; int len = strlen(s2); // contains the length of search string while(s1[n] != '\0') { if(s1[n] == s2[m]) { // if first character of search string matches // keep on searching while(s1[n] == s2[m] && s1[n] !='\0') { n++; m++; } // if we sequence of characters matching with the length of searched string if(m == len && (s1[n] == ' ' || s1[n] == '\0')) { // BINGO!! we find our search string. times++; } } else { // if first character of search string DOES NOT match while(s1[n] != ' ') { // Skip to next word n++; if(s1[n] == '\0') break; } } n++; m=0; // reset the counter to start from first character of the search string. } if(times > 0) { printf("'%s' appears %d time(s)\n", s2, times); } else { printf("'%s' does not appear in the sentence.\n", s2); } return 0; } C示例用于反转String的程序 C实例 交互字符串