Spring MVC - 多动作控制器示例 Spring MVC - 简单的URL处理程序映射示例 Spring MVC - 属性方法名称解析器示例 以下示例说明如何使用Spring Web MVC框架使用Multi Action Controller。所述 MultiActionController 类有助于与他们的方法的多个网址在单个控制器中分别进行映射。 package com.codingdict; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.web.servlet.ModelAndView; import org.springframework.web.servlet.mvc.multiaction.MultiActionController; public class UserController extends MultiActionController{ public ModelAndView home(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView model = new ModelAndView("home"); model.addObject("message", "Home"); return model; } public ModelAndView add(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView model = new ModelAndView("user"); model.addObject("message", "Add"); return model; } public ModelAndView remove(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView model = new ModelAndView("user"); model.addObject("message", "Remove"); return model; } } <bean class = "org.springframework.web.servlet.handler.BeanNameUrlHandlerMapping"/> <bean name = "/home.htm" class = "com.codingdict.UserController" /> <bean name = "/user/*.htm" class = "com.codingdict.UserController" /> 例如,使用上面的配置,如果URI 请求/home.htm,DispatcherServlet会将请求转发给UserController home() 方法。 请求user / add.htm,DispatcherServlet会将请求转发给UserController的 add() 方法。 请求user / remove.htm,DispatcherServlet会将请求转发给UserController的 remove() 方法。 首先,让我们使用一个可用的Eclipse IDE,并坚持以下步骤,使用Spring Web Framework开发基于动态表单的Web应用程序。 序号 描述 1 在Spring MVC - Hello World章节中解释,在com.codingdict包下创建一个名为TestWeb的项目。 2 在com.codingdict包下创建一个Java类UserController。 3 在jsp子文件夹下创建视图文件home.jsp和user.jsp。 4 最后一步是创建源文件和配置文件的内容并导出应用程序,如下所述。 UserController.java package com.codingdict; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.web.servlet.ModelAndView; import org.springframework.web.servlet.mvc.multiaction.MultiActionController; public class UserController extends MultiActionController{ public ModelAndView home(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView model = new ModelAndView("home"); model.addObject("message", "Home"); return model; } public ModelAndView add(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView model = new ModelAndView("user"); model.addObject("message", "Add"); return model; } public ModelAndView remove(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView model = new ModelAndView("user"); model.addObject("message", "Remove"); return model; } } TestWeb-servlet.xml <beans xmlns = "http://www.springframework.org/schema/beans" xmlns:context = "http://www.springframework.org/schema/context" xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation = " http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <bean class = "org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name = "prefix" value = "/WEB-INF/jsp/"/> <property name = "suffix" value = ".jsp"/> </bean> <bean class = "org.springframework.web.servlet.handler.BeanNameUrlHandlerMapping"/> <bean name = "/home.htm" class = "com.codingdict.UserController" /> <bean name = "/user/*.htm" class = "com.codingdict.UserController" /> </beans> home.jsp <%@ page contentType = "text/html; charset = UTF-8" %> <html> <head> <meta http-equiv = "Content-Type" content = "text/html; charset = ISO-8859-1"> <title>Home</title> </head> <body> <a href = "user/add.htm" >Add</a> <br> <a href = "user/remove.htm" >Remove</a> </body> </html> user.jsp <%@ page contentType = "text/html; charset = UTF-8" %> <html> <head> <title>Hello World</title> </head> <body> <h2>${message}</h2> </body> </html> 完成创建源文件和配置文件后,导出应用程序。右键单击您的应用程序,使用 Export→WAR File 选项并将 TestWeb.war 文件保存在Tomcat的webapps文件夹中。 现在,启动Tomcat服务器并确保您可以使用标准浏览器从webapps文件夹访问其他网页。现在,尝试一个URL - http:// localhost:8080 / TestWeb / home.htm ,如果Spring Web Application的一切正常,我们将看到以下屏幕。 尝试URL http:// localhost:8080 / TestWeb / user / add.htm ,如果Spring Web Application的一切正常,我们将看到以下屏幕。 Spring MVC - 简单的URL处理程序映射示例 Spring MVC - 属性方法名称解析器示例