Spring MVC - 参数方法名称解析器示例


以下示例说明如何使用Spring Web MVC框架使用多操作控制器的参数方法名称解析器。所述 MultiActionController 类有助于与他们的方法的多个网址在单个控制器中分别进行映射。

package com.codingdict;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.multiaction.MultiActionController;

public class UserController extends MultiActionController{

   public ModelAndView home(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Home");
      return model;
   }

   public ModelAndView add(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Add");
      return model;
   }

   public ModelAndView remove(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Remove");
      return model;
   }
}
<bean class = "com.codingdict.UserController">
   <property name = "methodNameResolver">
      <bean class = "org.springframework.web.servlet.mvc.multiaction.ParameterMethodNameResolver">
         <property name = "paramName" value = "action"/>
      </bean>
   </property>
</bean>

例如,使用上面的配置,如果URI -

  • 请求/user/*.htm?action=home,DispatcherServlet会将请求转发给UserController home() 方法。

  • 请求/user/*.htm?action=add,DispatcherServlet会将请求转发给UserController的 add() 方法。

  • 请求/user/*.htm?action=remove,DispatcherServlet会将请求转发给UserController的 remove() 方法。

首先,让我们使用一个可用的Eclipse IDE,并遵循以下步骤使用Spring Web Framework开发基于动态表单的Web应用程序。

序号 描述
1 在Spring MVC - Hello World章节中解释,在com.codingdict包下创建一个名为TestWeb的项目。
2 在com.codingdict包下创建一个Java类UserController。
3 在jsp子文件夹下创建一个视图文件user.jsp。
4 最后一步是创建源文件和配置文件的内容并导出应用程序,如下所述。

UserController.java

package com.codingdict;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.multiaction.MultiActionController;

public class UserController extends MultiActionController{

   public ModelAndView home(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Home");
      return model;
   }

   public ModelAndView add(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Add");
      return model;
   }

   public ModelAndView remove(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Remove");
      return model;
   }
}

TestWeb-servlet.xml

<beans xmlns = "http://www.springframework.org/schema/beans"
   xmlns:context = "http://www.springframework.org/schema/context"
   xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation = "
   http://www.springframework.org/schema/beans     
   http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
   http://www.springframework.org/schema/context
   http://www.springframework.org/schema/context/spring-context-3.0.xsd">

   <bean class = "org.springframework.web.servlet.view.InternalResourceViewResolver">
      <property name = "prefix" value = "/WEB-INF/jsp/"/>
      <property name = "suffix" value = ".jsp"/>
   </bean>

   <bean class = "org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping">
      <property name = "caseSensitive" value = "true" />
   </bean>
   <bean class = "com.codingdict.UserController">
      <property name = "methodNameResolver">
         <bean class = "org.springframework.web.servlet.mvc.multiaction.ParameterMethodNameResolver">
            <property name = "paramName" value = "action"/>
         </bean>
      </property>
   </bean>
</beans>

user.jsp

<%@ page contentType="text/html; charset=UTF-8" %>
<html>
   <head>
      <title>Hello World</title>
   </head>
   <body>
      <h2>${message}</h2>  
   </body>
</html>

完成创建源文件和配置文件后,导出应用程序。右键单击您的应用程序,使用 Export→WAR File 选项并将 TestWeb.war 文件保存在Tomcat的webapps文件夹中。

现在,启动Tomcat服务器并确保您可以使用标准浏览器从webapps文件夹访问其他网页。现在,尝试一个URL - http:// localhost:8080 / TestWeb / user / test.htm?action = home ,如果Spring Web Application的一切正常,我们将看到以下屏幕。

弹簧多动作控制器