Java根据栈匹配括号 Java节点栈 Java 队列基类 Java根据栈匹配括号 package data_structures.Stacks; import java.util.Scanner; import java.util.Stack; /** * * The nested brackets problem is a problem that determines if a sequence of * brackets are properly nested. A sequence of brackets s is considered properly * nested if any of the following conditions are true: - s is empty - s has the * form (U) or [U] or {U} where U is a properly nested string - s has the form * VW where V and W are properly nested strings For example, the string * "()()[()]" is properly nested but "[(()]" is not. The function called * is_balanced takes as input a string S which is a sequence of brackets and * returns true if S is nested and false otherwise. * * @author akshay sharma * @date: 2017-10-17 * */ class BalancedBrackets { /** * * @param s * @return */ static boolean is_balanced(String s) { Stack<Character> bracketsStack = new Stack<>(); char[] text = s.toCharArray(); for (char x : text) { switch (x) { case '{': case '<': case '(': case '[': bracketsStack.push(x); break; case '}': if (bracketsStack.peek() == '{') { bracketsStack.pop(); break; } else { return false; } case '>': if (bracketsStack.peek() == '<') { bracketsStack.pop(); break; } else { return false; } case ')': if (bracketsStack.peek() == '(') { bracketsStack.pop(); break; } else { return false; } case ']': if (bracketsStack.peek() == '[') { bracketsStack.pop(); break; } else { return false; } } } return bracketsStack.empty(); } /** * * @param args * @TODO remove main method and Test using JUnit or other methodology */ public static void main(String args[]) { try (Scanner in = new Scanner(System.in)) { System.out.println("Enter sequence of brackets: "); String s = in.nextLine(); if (is_balanced(s)) { System.out.println(s + " is balanced"); } else { System.out.println(s + " ain't balanced"); } } } } Java节点栈 Java 队列基类